What Zoom Lens Covers 10–4 mm FOV and 5 μm Defects?

A practical machine-vision example using a 2/3" 5 MP camera at 80–100 mm working distance for chip surface inspection.

Quick Answer
Camera: HIKROBOT MV-CS050-10GC (5 MP, 2448 × 2048, 2/3" class, C-mount)
Sensor active area: ≈ 8.45 × 7.07 mm (3.45 μm pixels; calculated)
Required FOV: 10 × 10 mm down to 4 × 4 mm (continuous zoom)
Required WD: 80–100 mm
Minimum feature: 5–10 μm (scratches, pits, edge chipping, IC surface)
Calculated magnification: 0.71× (10 mm FOV) to 1.77× (4 mm FOV); zoom ratio ≈ 2.5:1
Recommended configuration: A) 6.5X coaxial zoom lens (0.7×–4.5×) + 0.5X TV adapter + coaxial illumination — cost-effective; B) 12.5X zoom lens LZL-12100 (0.58×–7.5×) with native 1X TV path — higher image quality
Important limitation: at the 10 mm FOV position a 5 μm feature spans only ≈ 1 pixel and cannot be reliably detected; 5 μm inspection is only realistic at the 4 mm FOV position.

Customer Requirement

ItemValue
CameraHIKROBOT MV-CS050-10GC, 5 MP, 2448 × 2048, C-mount
Sensor class2/3" (active area ≈ 8.45 × 7.07 mm, 3.45 μm pixels, calculated)
FOV range10 × 10 mm → 4 × 4 mm
Working distance80–100 mm
Minimum feature5–10 μm
TargetsScratches, pits, edge chipping, fine surface texture, IC surface defects

Required Magnification Calculation

The required magnification is calculated from the sensor and the FOV — before looking at any nominal zoom ratio:

β = sensor short side ÷ required FOV

  • 10 × 10 mm FOV: β = 7.07 ÷ 10 = 0.71× (the other direction then covers 8.45 ÷ 0.71 ≈ 11.9 mm)
  • 4 × 4 mm FOV: β = 7.07 ÷ 4 = 1.77× (horizontal ≈ 4.8 mm)
  • Required zoom ratio: 1.77 ÷ 0.71 ≈ 2.5 : 1

Both candidate POMEAS zoom bodies cover 0.71–1.77× natively. The TV adapter and auxiliary lens do not create this range — they decide where in the zoom travel each FOV sits, and with it the working resolution and depth of field.

Can 5–10 μm Features Be Detected?

Object-side sampling (calculated): at 4 mm FOV, 4/2448 = 1.63 μm/px (H) and 4/2048 = 1.95 μm/px (V); at 10 mm FOV, 4.09 / 4.88 μm/px.

FeatureAt 4 mm FOVAt 10 mm FOVEngineering verdict
5 μm≈ 2.6–3.1 px≈ 1.0–1.2 pxBorderline at 4 mm (also near the optical-resolution limit); not detectable at 10 mm
10 μm≈ 5.1–6.1 px≈ 2.0–2.4 pxRobust at 4 mm; marginal at 10 mm
Engineering Rule: A 5 μm feature occupying only around 1 pixel cannot be considered a robust inspection condition. Sampling of roughly 3 pixels across the feature is the practical minimum, and the optical resolution, illumination contrast and focus stability must support it. "The feature can be seen" and "the defect can be reliably detected" are not the same statement.

Recommended Optical Configuration

Configuration A — Cost-effective / practical: 6.5X coaxial zoom + 0.5X TV adapter + 1X front path + coaxial light

  • Why it fits: the 6.5X coaxial zoom body (PMS-LZ-63101 series, 0.7×–4.5×, WD 87 ± 2 mm) with a 0.5X TV adapter gives an effective range of 0.35–2.25×, covering 0.71–1.77×; WD 87 mm sits inside the 80–100 mm window; the coaxial version carries the beamsplitter for reflective chip surfaces.
  • Advantages: cost-effective; large FOV headroom (down to ≈ 24 mm width at the bottom of the travel); motorized and detent variants exist (e.g. LZ-650104 motorized version).
  • Limitations: the 0.5X rear reduction halves the image-side NA, so the diffraction-limited object-side resolution at the 4 mm FOV position is roughly double that of a native 1X path (≈ 8–11 μm, calculated estimate); depth of field at the 4 mm position ≈ 0.13 mm (interpolated from the datasheet). 5 μm detection must be verified on the bench.
  • Best suited for: 10 μm-class scratches and pits, cost-driven builds, multi-dish/multi-chip overview plus detail re-inspection.

Configuration B — Higher image quality: 12.5X zoom + 1X TV path (no front reduction)

  • Why it fits: LZL-12100 (0.58×–7.5×, zoom ratio 12.5:1, telecentric design, WD 77.4 ± 2 mm) covers 0.71–1.77× natively — the 4 mm FOV is reached at ≈ 1.8× body magnification with no reduction optics behind it.
  • Advantages: the native 1X TV path preserves resolution — datasheet resolution is 7.8 μm @ 1.0× and ≈ 5.6 μm @ 1.5–1.8× (interpolated); depth of field at the 4 mm position ≈ 0.3 mm; 12.5:1 ratio leaves margin for future smaller FOVs; electric and coaxial variants (e.g. LZL-12101D) are available.
  • Limitations: WD 77.4 ± 2 mm is below the stated 80 mm lower bound — the installation envelope must be verified; if 80 mm is a hard limit, a 0.75X auxiliary lens extends the WD (resulting WD to be confirmed with POMEAS).
  • Best suited for: 5 μm-class surface defects, IC/chip surface inspection where optical quality comes first.

A properly matched native 1X TV optical path is generally preferred for high-resolution inspection when the required FOV can be achieved through a matched objective or auxiliary lens. Low-quality or small-diameter 0.5X TV adapters can cause sampling-density reduction, edge-image degradation, additional aberrations and lower contrast — but a high-quality, correctly matched TV adapter also works normally in machine vision systems.

TV Adapter vs Auxiliary Lens

A TV adapter acts on the camera side (image side): it scales the image onto the sensor. An auxiliary lens (front lens) acts on the object side: it changes magnification, FOV and working distance of the front group. They are not interchangeable "0.5×" parts: a 0.5X TV adapter halves the image-side NA and therefore costs resolution, while a front auxiliary changes the object-side geometry and the WD. High-resolution inspection should keep the 1X TV path whenever the FOV can be reached with a matched front lens.

Lighting Recommendation

Chip and IC surfaces are flat and specular. Coaxial illumination sends light down the optical axis; flat areas reflect back into the lens and appear bright, while scratches, pits and edge chipping scatter light sideways and appear dark — exactly the contrast these defects need. The coaxial versions of both zoom bodies carry an integrated beamsplitter, so no extra beamsplitter cube is required. Ring lights are suitable for textured or non-specular surfaces, not for this case.

Engineering Conclusion

For a 2/3" 5 MP camera (2448 × 2048) requiring approximately 10 × 10 mm to 4 × 4 mm FOV at 80–100 mm WD, the required magnification is calculated as 0.71× to 1.77× — a zoom ratio of about 2.5:1, which both the 6.5X and 12.5X zoom bodies cover without reduction optics.

A 5 μm feature spans only ≈ 1 pixel at the 10 mm FOV position, so 5 μm inspection results in a hard requirement: it must be performed at the 4 mm FOV position, where 5 μm spans ≈ 3 pixels and remains near the system's optical limit.

When the 5 μm requirement is confirmed, the native 1X TV optical path of Configuration B should be preferred; the 0.5X TV adapter of Configuration A is suitable when 10 μm-class defects are the target and cost is the deciding factor. Both configurations' WD and depth of field should be verified on the actual bench before release.

FAQ

How do I calculate lens magnification from FOV?

Divide the sensor dimension by the required object-side FOV. For square FOVs, use the sensor's short side so the full area fits: β = 7.07 mm ÷ 4 mm = 1.77×. Then check the other direction (8.45 ÷ 1.77 ≈ 4.8 mm) to confirm coverage. Do this calculation before comparing nominal zoom ratios.

Can a 5 MP camera detect a 5 μm defect?

It depends on the FOV, not on the megapixels alone. At 4 mm FOV a 5 μm feature spans ≈ 2.6–3 pixels (borderline, needs good contrast); at 10 mm FOV it spans ≈ 1 pixel and cannot be reliably detected. Sampling is necessary but not sufficient — lens resolution, illumination contrast and focus stability must also support it.

Does a 0.5X TV adapter reduce image quality?

A reduction adapter scales the image down behind the lens and halves the image-side NA, so the diffraction-limited object-side resolution roughly doubles compared with a native 1X path at the same FOV. How much this matters depends on the adapter's optical quality — a well-matched 0.5X TV adapter works normally, but the loss should be verified on the bench when 5 μm features are the target.

What is the difference between a TV adapter and an auxiliary lens?

A TV adapter works on the image side: it scales the already-formed image onto the sensor. An auxiliary lens works on the object side: it changes magnification, FOV and working distance of the front group. The same "0.5×" label describes two physically different operations and they should not be treated as interchangeable components.

Why is coaxial illumination used for chip inspection?

Chip surfaces are flat and reflective. Coaxial illumination illuminates along the optical axis so flat areas return light to the lens and appear bright, while scratches, pits and chipped edges scatter light and appear dark. This produces the bright-field contrast needed for surface-defect detection on specular samples.

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