50 mm/s at 50 µm Needs a 1 kHz Line Rate

A line-scan camera samples the part once per line, so the resolution along the motion direction is set purely by how far the belt travels between two lines. To hold 50 µm per line at 50 mm/s the camera has to run at 1 kHz — that is 50 mm/s ÷ 0.05 mm. Each line then has 1000 µs to expose and read out, which is the number that decides whether your light is bright enough, and the cross-web axis has to be sampled at the same 50 µm if you want square pixels.

The numbers for this combination

Belt speed50 mm/s
Along-motion resolution (per line)50 µm
Required line rate1 kHz
Line period (1 / line rate)1000 µs
Exposure cap for 1 px of smear1000 µs
Exposure cap for ½ px of smear500 µs
Exposure cap for ¼ px of smear250 µs
Lines per metre of product20000

The formula, and the unit that catches people out

Line rate is speed divided by resolution, not multiplied by it. Written with consistent units, line rate = belt speed ÷ resolution along the motion direction. In millimetres per second and millimetres per line the result is lines per second; divide by 1000 for kHz. Dividing micrometres by millimetres (a factor of 1000) is the single most common error in this calculation — it produces an answer three orders of magnitude out and is easy to spot because no camera on the market runs that fast.

Substitution: 50 mm/s ÷ 0.05 mm = 1000 lines/s = 1 kHz

Exposure arithmetic

Smear along the motion direction is speed × exposure time. To keep it under a chosen fraction of the 50 µm sampling interval, the exposure has to satisfy exposure ≤ fraction × 50 µm ÷ 50 mm/s. At one full pixel of smear that ceiling is 1000 µs; at half a pixel it is 500 µs. In practice you aim well below the ceiling and make up the light with a brighter bar, because a real line also has readout and jitter on top.

What other line rates give you at this speed

Line rateTravel per lineLines per metre½ px exposure cap
5 kHz10 µm100000100 µs
10 kHz5 µm20000050 µs
20 kHz2.5 µm40000025 µs
40 kHz1.2 µm80000012.5 µs
80 kHz0.6 µm16000006.2 µs

Same belt speed, different camera setting. Doubling the line rate halves the resolution interval and halves the exposure budget — the two move together, which is why a faster line always costs light.

Keeping the pixels square across the web

The line rate sets the sampling along the motion direction; the lens and camera pixel pitch set the sampling across it. For equal sampling in both directions the lens has to run at magnification = pixel pitch ÷ resolution. On this page that is 50 µm of along-motion sampling, so a 5 µm pitch camera needs 0.1X, a 10 µm pitch needs 0.2X and a 20 µm pitch needs 0.4X. Get this wrong and the part is stretched or squashed by the ratio of the two, even though each axis looks sharp on its own.

CameraPixel pitchLine lengthMagnification for square pixelsResulting FOV widthInside PMS-LLC
2K14 µm28.67 mm✓ 0.28X102.4 mmyes
4K7 µm28.67 mm✗ 0.14X204.8 mmno
4K10 µm40.96 mm✗ 0.2X204.8 mmno
8K7 µm57.34 mm✗ 0.14X409.6 mmno
8K10 µm81.92 mm✗ 0.2X409.6 mmno
16K5 µm81.92 mm✗ 0.1X819.2 mmno

Line length is pixel count × pitch and must stay inside the 82 mm image circle of the PMS-LLC series. The FOV width is simply pixel count × 50 µm, independent of which camera you choose — a larger sensor buys field, not resolution. At its widest setting the family images 82 mm ÷ 0.22X ≈ 373 mm, so a wider web is a multi-camera line, not a wider lens.

A cross in the last column is not a lens problem: the camera is over-resolved for this interval, so its pitch ÷ 50 µm falls below the 0.22X bottom of the band. The fix is a coarser-pitch camera with fewer pixels — no lens can create 0.1X on an 82 mm image circle without a field wider than the line can hold.

PMS-LLC line-scan lenses and where they sit

These are the published POMEAS line-scan lenses for a 16K line (82 mm image circle, M72 mount, F4.0–F16, under 0.002% distortion). Pick the model whose magnification band contains the figure in the table above.

ModelMagnificationWorking distanceResolving powerDistortionMount
PMS-LLC026-14640M-M720.22X – 0.3X752 / 644 / 571 mm5 μm<0.002%M72
PMS-LLC033-14640M-M720.3X – 0.37X482 - 571 mm5 μm<0.002%M72
PMS-LLC05-14640M-M720.47X – 0.54X417 / 383 / 357 mm5 μm<0.002%M72
PMS-LLC075-14640M-M720.7X – 0.85X304 / 286 / 267 mm5 μm<0.002%M72
PMS-LLC1-14640M-M720.92X – 1.08X见规格书5 μm<0.002%M72
PMS-LLC133-14640M-M721.33X216 mm5 μm<0.002%M72
PMS-LLC2-14640M-M721.75X – 2.25X179 - 690 mm5 μm<0.002%M72
PMS-LLC3-14640M-M723X – 3.5X157 / 150 / 144 mm10 μm<0.002%M72

Values are as published on each product page. Where a model offers three settings the working distances are listed in the same order.

What actually limits this combination

Three things break before the geometry does. First, light: at 1000 µs per line the bar has to deliver roughly 1× the energy per line that a 1 ms area-camera exposure would, so line-scan illumination is sized in W per metre, not in lumens. Second, the trigger: the line rate has to follow an encoder, not a timer, or belt-speed variation turns into resolution variation. Third, vibration and lens resolving power — a lens quoted at 5 µm cannot deliver a 50 µm sample with margin if the mount rings at the line frequency.

Frequently asked questions

What line rate do I need for 50 mm/s at 50 µm?

1 kHz. Divide the speed by the resolution interval: 50 mm/s ÷ 50 µm (= 0.05 mm) = 1000 lines/s = 1 kHz. The line period is the reciprocal, 1000 µs, and one metre of product is sampled 20000 times.

What is the maximum exposure time at this line rate?

The hard ceiling is one line period, 1000 µs, which already allows a full pixel of smear. For half a pixel it is 500 µs and for a quarter pixel 250 µs. Treat the half-pixel figure as the working target for measurement and the full-pixel figure as the limit for presence detection.

Why does the lens magnification have to change when I change the line rate?

It does not follow the line rate directly — it follows the resolution you end up with. Because this page fixes 50 µm along the motion direction, the cross-web axis needs the same 50 µm, and that means magnification = pixel pitch ÷ 50 µm. Halve the resolution target and the magnification doubles, so a line-rate change usually pulls a lens change with it.

How fast can the belt run before this stops working?

Until the line rate leaves the camera specification. Holding 50 µm, a 100 kHz camera would reach 5000 mm/s. Beyond that you either accept a coarser resolution interval or split the web across two cameras so each runs at half the line rate.

Do I need an encoder, or is a fixed line rate enough?

Use an encoder whenever the part has to be measured or stitched without distortion. A fixed line rate assumes the belt speed never varies; a 2% speed error becomes a 2% length error in the image, which is larger than most of the tolerances this resolution was chosen for. Fixed rate is acceptable for presence and label checks only.

Is 1 kHz realistic for one camera?

Yes. 1 kHz is a comfortable operating point for a line-scan camera, and at that speed most camera families still offer a second tap or a binning mode if you need more light.

Related reading

The method behind these numbers, and the pages that continue the calculation: motion blur: exposure time against conveyor speed, magnification table: sensor width × field of view, inline cycle time and station count, real working distances by model, PMS-LLC05 16K line-scan lens. Working on a line that does not match any row here? Send the speed and the resolution you need: talk to an application engineer.

Back to the full line-scan timing table: speed × resolution → line rate

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